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05.10.2006, 15:13
синтаксис php нарушен
PHP код:
function themefooter() {
global $index, $bgcolor1, $bgcolor2, $bgcolor3, $module_name;
if(defined('HOME_FILE')) {
// echo "</td><td> </td><td valign=\"top\" bgcolor=$bgcolor1>";
echo "</td><td> </td><td valign=\"top\" BACKGROUND=\"themes/Sand_Journey_new/images/background.gif\">";
blocks(right);
echo "</td>";
echo "</td></tr></table></td></tr></table>";
echo "<center>";
echo ads(2);
echo "</center>";
} else {
// echo "</td><td> </td><td valign=\"top\" bgcolor=$bgcolor1>";
echo "</td><td> </td><td valign=\"top\" BACKGROUND=\"themes/Sand_Journey_new/images/background.gif\">";
blocks(right);
echo "</td>";
echo "</td></tr></table></td></tr></table>";
echo "<center>";
?>ССЫЛКИ<?php
echo "</center>";
}
}
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