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24.02.2006, 23:41
найдите:
PHP код:
$result3 = $db->sql_query("SELECT tid, title FROM ".$prefix."_encyclopedia_text WHERE UPPER(title) LIKE '$ltr%' AND eid='$eid'");
Замените на:
PHP код:
$result3 = $db->sql_query("SELECT tid, title FROM ".$prefix."_encyclopedia_text WHERE UPPER(title) LIKE '$ltr%' AND eid='$eid ORDER BY title'");
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